t^2+t/(2)=28

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Solution for t^2+t/(2)=28 equation: 


t in (-oo:+oo)

t^2+t/2 = 28 // - 28

t^2+t/2-28 = 0

t^2+1/2*t-28 = 0

DELTA = (1/2)^2-(-28*1*4)

DELTA = 449/4

DELTA > 0

t = ((449/4)^(1/2)-1/2)/(1*2) or t = (-(449/4)^(1/2)-1/2)/(1*2)

t = ((449/4)^(1/2)-1/2)/2 or t = (-((449/4)^(1/2)+1/2))/2

t in { (-((449/4)^(1/2)+1/2))/2, ((449/4)^(1/2)-1/2)/2 }

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